Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in various fields such as engineering, finance, etc. Here, we will discuss the square root of 5.3.
The square root is the inverse of the square of the number. 5.3 is not a perfect square. The square root of 5.3 is expressed in both radical and exponential form. In radical form, it is expressed as √5.3, whereas (5.3)^(1/2) in exponential form. √5.3 ≈ 2.3022, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is typically used for perfect square numbers. However, for non-perfect square numbers, methods like the long-division method and approximation method are used. Let us now learn the following methods:
The long division method is particularly used for non-perfect square numbers. In this method, we calculate the square root step-by-step to achieve a more accurate result.
Step 1: Begin by grouping the digits of the number from right to left. Since 5.3 is a decimal, we consider it as 5.3000.
Step 2: Find the largest number whose square is less than or equal to 5. The number is 2 because 2 × 2 = 4, which is less than 5. The quotient is 2, and the remainder is 1 (5 - 4).
Step 3: Bring down the next pair of digits, which are 30, to make the new dividend 130. Double the quotient (2), giving us 4, and write it below. Now, find a number n such that 4n × n is less than or equal to 130.
Step 4: The number n is 2, because 42 × 2 = 84, which is less than 130. Subtract 84 from 130 to get 46.
Step 5: Repeat the process by bringing down the next pair of zeros, making the dividend 4600. Double the current quotient (22) to get 44, then find a new n.
Step 6: Continuing this process gives us an approximate square root of 2.3022.
The approximation method is an easy way to find the square root of a given number by locating the closest perfect squares.
Step 1: Identify the closest perfect squares to 5.3.
The closest perfect square less than 5.3 is 4 (√4 = 2), and greater than 5.3 is 9 (√9 = 3). Therefore, √5.3 falls between 2 and 3.
Step 2: Using interpolation, we calculate: (Given number - smallest perfect square) / (Greater perfect square - smallest perfect square). (5.3 - 4) / (9 - 4) = 1.3 / 5 = 0.26
Step 3: Add the result of the interpolation to the square root of the smaller perfect square: 2 + 0.26 ≈ 2.26, which is a rough estimate.
Students often make mistakes while finding the square root, such as ignoring the negative square root or skipping steps in the long division method. Here are some common mistakes and how to avoid them:
Can you help Max find the area of a square box if its side length is given as √5.3?
The area of the square is 5.3 square units.
The area of the square = side².
The side length is given as √5.3.
Area of the square = side² = √5.3 × √5.3 = 5.3.
Therefore, the area of the square box is 5.3 square units.
A square-shaped park has an area of 5.3 square meters. If each of the sides is √5.3, what will be the square meters of half of the park?
2.65 square meters
Since the park is square-shaped, divide the given area by 2 to find half: 5.3 / 2 = 2.65
So, half of the park measures 2.65 square meters.
Calculate √5.3 × 5.
11.511
First, find the square root of 5.3, which is approximately 2.3022.
Multiply 2.3022 by 5: 2.3022 × 5 = 11.511
What will be the square root of (5.3 + 0.7)?
The square root is approximately 2.4495
First, calculate the sum of 5.3 + 0.7: 5.3 + 0.7 = 6
Then, find the square root of 6: √6 ≈ 2.4495
Therefore, the square root of (5.3 + 0.7) is approximately ±2.4495.
Find the perimeter of a rectangle if its length ‘l’ is √5.3 units and the width ‘w’ is 3 units.
The perimeter of the rectangle is approximately 10.6044 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√5.3 + 3) = 2 × (2.3022 + 3) ≈ 2 × 5.3022 ≈ 10.6044 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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