Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 1.48.
The square root is the inverse of the square of the number. 1.48 is not a perfect square. The square root of 1.48 is expressed in both radical and exponential form. In the radical form, it is expressed as √1.48, whereas (1.48)^(1/2) in the exponential form. √1.48 ≈ 1.21655, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long division method and approximation method are used. Let us now learn the following methods:
Prime factorization is the process of expressing a number as the product of its prime factors. Since 1.48 is not a perfect square, it cannot be represented through integer prime factorization. Therefore, calculating the square root of 1.48 using prime factorization is impractical.
The long division method is particularly used for non-perfect square numbers. In this method, we find the square root step by step by considering pairs of digits from the decimal point.
Step 1: To begin with, we need to group the number. For 1.48, we consider it as 1.48 since it's a decimal number.
Step 2: Find a number 'n' such that n² ≤ 1. The number is 1 because 1² = 1.
Step 3: Subtract 1 from 1, bringing down 48, which results in 48 as the new dividend.
Step 4: Double the number in the quotient (which is 1), making it 2. Find a digit 'd' such that 2d × d ≤ 48. The digit is 2 since 22 × 2 = 44.
Step 5: Subtract 44 from 48, yielding a remainder of 4. Bring down two zeroes, making the new dividend 400.
Step 6: Repeat the process to find the next digits. Continue this process to get more decimal places.
The square root of 1.48 is approximately 1.21655.
Approximation is an easier method to find the square root of a given number.
Step 1: Identify two consecutive perfect squares between which 1.48 lies. The closest perfect squares are 1 (1²) and 4 (2²). √1.48 falls between 1 and 2.
Step 2: Using interpolation, we can estimate the value more precisely.
By estimating, we find that √1.48 is approximately 1.21655.
Students often make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Let us explore these common errors in detail.
Can you help Max find the area of a square box if its side length is given as √1.48?
The area of the square is approximately 1.4808 square units.
The area of a square is given by side².
The side length is √1.48.
Area of the square = (√1.48)² = 1.48.
Therefore, the area of the square box is approximately 1.48 square units.
A square-shaped building measuring 1.48 square feet is built; if each of the sides is √1.48, what will be the square feet of half of the building?
0.74 square feet
We can divide the given area by 2 as the building is square-shaped.
Dividing 1.48 by 2 = 0.74
So half of the building measures 0.74 square feet.
Calculate √1.48 x 5.
Approximately 6.08275
First, find the square root of 1.48, which is approximately 1.21655.
Then multiply 1.21655 by 5.
So, 1.21655 x 5 ≈ 6.08275.
What will be the square root of (1.48 + 0.52)?
The square root is 1.414
To find the square root, calculate the sum of (1.48 + 0.52). 1.48 + 0.52 = 2, and then √2 ≈ 1.414.
Therefore, the square root of (1.48 + 0.52) is approximately ±1.414.
Find the perimeter of the rectangle if its length ‘l’ is √1.48 units and the width ‘w’ is 3 units.
We find the perimeter of the rectangle as approximately 8.4331 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√1.48 + 3) ≈ 2 × (1.21655 + 3)
= 2 × 4.21655
≈ 8.4331 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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