Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 1.04.
The square root is the inverse of the square of the number. 1.04 is not a perfect square. The square root of 1.04 is expressed in both radical and exponential form. In the radical form, it is expressed as √1.04, whereas (1.04)^(1/2) in the exponential form. √1.04 ≈ 1.0198, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where the long-division method and approximation method are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. However, since 1.04 is a decimal, we can't directly apply prime factorization in the traditional sense used for integers. Thus, calculating 1.04 using prime factorization is not feasible.
The long division method is particularly used for non-perfect square numbers, including decimals. Let us now learn how to find the square root of 1.04 using the long division method, step by step:
Step 1: Consider 1.04 as 104 by moving the decimal two places to the right. Group the digits in pairs from right to left.
Step 2: Find a number whose square is less than or equal to 1. The number is 1. Subtract 1 from 1 to get a remainder of 0.
Step 3: Bring down the next pair of digits, which is 04, to make it 104. Double the current quotient (1), resulting in 2, and use it as the new divisor.
Step 4: Determine a digit n such that 2n × n ≤ 104. The suitable digit is 4.
Step 5: Subtract 104 from 104 to get a remainder of 0. Since we have reached the decimal point, place a decimal in the quotient.
Step 6: The quotient now is 1.0. Continue the process to refine the decimal places as needed.
The square root of 1.04 is approximately 1.0198.
The approximation method is another approach for finding square roots, especially for decimals. Let us learn how to find the square root of 1.04 using approximation:
Step 1: Identify the perfect squares around 1.04. The closest perfect squares are 1 (1^2) and 1.21 (1.1^2). Therefore, √1.04 is between 1 and 1.1.
Step 2: Use interpolation or successive approximation to refine the square root value. A rough estimate of the decimal value between 1 and 1.1 gives √1.04 ≈ 1.0198.
Students often make mistakes while finding square roots, such as overlooking the negative square root or skipping steps in methods like long division. Let us explore common mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √1.04?
The area of the square is 1.081 square units.
The area of the square = side².
The side length is given as √1.04.
Area of the square = (√1.04)² = 1.04.
Therefore, the area of the square box is 1.04 square units.
A square-shaped garden measures 1.04 square meters. If each side is √1.04 meters, what is the length of the garden's diagonal?
Approximately 1.442 meters.
The diagonal of a square with side length s is given by s√2.
Diagonal = √1.04 × √2 ≈ 1.0198 × 1.414 ≈ 1.442 meters.
Calculate √1.04 × 10.
Approximately 10.198.
First, find the square root of 1.04, which is approximately 1.0198.
Multiply by 10. So, 1.0198 × 10 ≈ 10.198.
What is the square root of (1.04 + 0.01)?
The square root is approximately 1.05.
Calculate (1.04 + 0.01) = 1.05.
Then, the square root of 1.05 is approximately 1.0247.
Find the perimeter of a rectangle if its length ‘l’ is √1.04 meters and the width ‘w’ is 1 meter.
Approximately 4.0396 meters.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√1.04 + 1) ≈ 2 × (1.0198 + 1) ≈ 2 × 2.0198 ≈ 4.0396 meters.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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