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Last updated on July 24th, 2025

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Multiplying Complex Numbers

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A complex number is written in the form z = a + ib, where i is the imaginary unit (i2 = -1) and a and b are real numbers. It involves applying the distributive property to compute the product of two complex numbers. In this article, let’s learn about the multiplication of complex numbers.

Multiplying Complex Numbers for UAE Students
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What is the multiplication of complex numbers?

The multiplication of complex numbers involves finding the product of two or more complex numbers using the distributive property.

 

That is, for two complex numbers: z1 = a + ib and z2 = c + id, the product of z1 and z2 is z1z2 = (a + ib) (c + id).

Professor Greenline from BrightChamps

What are the properties of the multiplication of complex numbers?

The multiplication of complex numbers follows similar properties to the real numbers. The properties are 

 

  • Commutative property
     
  • Associative property
     
  • Distributive property

 

Commutative property: It can be stated as the order of multiplication does not affect the result. For example, z1 × z2 = z2 × z1

 

Associative property: The associative property of complex numbers states that the order of grouping the complex numbers doesn't change the result. That is, z1 × (z2 × z3) = (z1 × z2) × z3

 

Distributive property: The distributive property states that z1 (z2 + z3) = z1z2 + z1z3

Professor Greenline from BrightChamps

How to multiply complex numbers in Cartesian form

Now, let’s learn how to multiply complex numbers in Cartesian form. In this form, we multiply the complex number term by term. 
 

That is, if z1 = a + ib and z2 = c + id. 

Then z1 × z2 = (a + ib) (c + id) 

= ac + a(id) + ib(c) + i2bd

= (ac - bd) +  i(ad + bc)

 

So, (a + ib) (c + id) = (ac - bd) +  i(ad + bc)

 

For example, find the product of Z1 = 3 + 2i and z2 = 1 + 4i
Z1z2 = (3 + 2i) (1 + 4i)

Using the formula for multiplying complex numbers, (a + ib) (c + id) = (ac - bd) +  i(ad + bc)

(3 + 2i) (1 + 4i) = ((3 × 1) - (2 × 4)) + i((3 × 4) + (2 × 1))

= (3 - 8) + i (12 + 2)

= -5 + 14i

Professor Greenline from BrightChamps

How to Multiply Complex Numbers in Polar Form

When multiplying complex numbers in polar form, we first multiply the moduli and then add the arguments. That is, when multiplying z1 = r1eiΘ1 and z2 = r2eiΘ2

Z1z2 = r1eiΘ1 × r2eiΘ2

= (r1 r2) eiΘ1 + iΘ2

= r1r2 ei(Θ1 + Θ2)
  

For example, multiplying z1 = 2eiπ/6 and z2 = 3eiπ/4

z1z2 = r1r2 ei(Θ1 + Θ2)

Here, r1 = 2

r2 = 3

Θ1 = π/6 

Θ2 = π/4

 

Multiplying moduli (r1r2) = 2 × 3 = 6

Adding the arguments = π/6 + π/4 

= 2π/12 + 3π/12

= 5π/12
 

So, 2eiπ/6 × 3eiπ/4 = 6ei5π/12

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Multiplication Of Complex Numbers with Real and Imaginary Numbers

The multiplication formula for complex numbers is  (a + ib) (c + id) = (ac - bd) +  i (ad + bc). When multiplying the complex number by a real number, let's consider b as 0. That is a (c + id) = ac + iad. 

 

For example: -5i (2 + 3i)

Using the formula, a (c + id) = ac + iad. 

Here, a = -5i

c = 2

d = 3i

Substituting the value, -5i (2 + 3i) = (-5i × 2) + (-5i × 3i)
= -10i + (-15i2)

Substituting i2 = -1

= -10i + 15 = 15 - 10i. 

Professor Greenline from BrightChamps

Squaring Complex Numbers

The formula for multiplying complex numbers is (a + ib) (c + id) = (ac - bd) +  i(ad + bc). When squaring a complex number, consider a = c and b = d, and then the formula becomes;

(a + ib)2 = (a×a - b × b) + i(ab + ba)

= (a2 - b2) + i (2ab)

 

For example, squaring 4 + 5i

(a + ib)2 = (a2 - b2) + i(2ab).

So, (4 + 5i) = (42 - (5i)2) + i(2 × 4 × 5)

= (16 - 25 × i2) + 40i

= 16 - 25 + 40i

= -9 + 40i

Professor Greenline from BrightChamps

Multiplicative Inverse Of Complex Numbers

The multiplicative inverse of a complex number z = a + ib is another complex number z-1, that is, z × z-1 = 1. For a complex number z = a + ib, the multiple inverse z-1 = z/|z|²

 

Here, z = a - ib, so, |z| = √a2 + b2

The formula for the multiplicative inverse: z-1 = z/|z|²

Where, conjugate: z = a - ib, and the modulus of the complex number is |z| = √a² + b²

Professor Greenline from BrightChamps

Real-world applications of Multiplying Complex Numbers

Complex number multiplication is used in various fields, like engineering, quantum mechanics, computer graphics, etc. In this section, we will discuss them in detail. 

 

  • In electrical engineering, complex number multiplication is used to calculate power, impedance, and phase shifts.

 

  • In quantum mechanics, it is used to describe and calculate quantum states. 

 

  • In 2D graphics, complex numbers are used in transformations such as rotation, scaling, and reflections. 

 

  • Cryptography involves complex numbers, especially in elliptic curve cryptography and quantum cryptography. 
     
Max Pointing Out Common Math Mistakes

Common Mistakes and How to Avoid Them in Multiplying Complex Numbers The students usually make mistakes when multiplying complex numbers, and mostly they repeat the same mistakes. In this section, we will discuss some common mistakes and ways to avoid them in multiplying complex numbers.

The students usually make mistakes when multiplying complex numbers, and mostly they repeat the same mistakes. In this section, we will discuss some common mistakes and ways to avoid them in multiplying complex numbers. 

Mistake 1

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Not applying the distributive property

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When multiplying complex numbers, students sometimes skip multiplying every term. So, always remember that when multiplying complex numbers, always use the distributive property. That is (a + ib) (c + id) = (ac - bd) +  i(ad + bc). 

Mistake 2

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Incorrect distribution of negative signs

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While solving a complex number with negative signs, students make mistakes in considering that sign. For calculating complex numbers, it is always advisable to ignore any signs.

Mistake 3

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Not recognizing i2 = -1

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Sometimes students forget to substitute the value of i2 with -1, which leads to errors, as the answer is not simplified. So always remember to expand the value of i² with -1.

Mistake 4

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Mixing up real and imaginary parts

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Mixing up real and imaginary parts, especially when combining the results. So, after expansion, always arrange as (ac - bd) +  i(ad + bc). 

Mistake 5

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Subtracting the arguments instead of adding them in the multiplication of polar form. 

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When multiplying complex numbers in polar form, students sometimes subtract the argument instead of adding, which is wrong. So always remember that when multiplying complex numbers in the polar form, we first multiply the moduli and then add the arguments.  

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Solved Examples of Multiplying Complex Numbers

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Problem 1

Find the product of (2 + 3i) × (4 + 5i)

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The product of (2 + 3i) × (4 + 5i) is -7 + 22i

Explanation

To multiply the complex number, we use the formula;

(a + ib) (c + id) = (ac - bd) +  i(ad + bc). 

Here, a = 2, b = 3, c = 4, and d = 5

(ac - bd) = 2 × 4 - 3 × 5 = 8 - 15 = -7

(ad + bc) = 2 × 5 + 3 × 4 = 10 + 12 = 22

So, the product is -7 + 22i

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Problem 2

Find the product of (1 + i) and (1-i) using the polar form

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The product is 2

Explanation

To find the product in polar form, we first convert each complex number to polar form. 

For 1 + i, 

r = √a2 + b2

= √1² + 1² = √2

Θ = tan-1(b/a) 

= tan-1(1/1) = 45°

Therefore, 1 + i = √2(cos45° + i sin45°)

 

For 1 - i, 

r = √1² + (-1)²

=√2

Θ = tan-1(-1/1) = -45°

Therefore, 1 + i = √2(cos(-45°) + i sin(-45°))

 

Here, r1r2 = √2 × √2 = 2

Θ1 + Θ2 = 45° + (-45°) = 0°

 

(1 + i)(1-i) = 2(cos0° + i sin0°) = 2.

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Problem 3

Find the product of √5 (cos15° + i sin15°) and √5 (cos 30° + i sin30°)

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The product of √5 (cos15° + i sin15°) and √5 (cos 30° + i sin30°) = 5(cos 45° + i sin45°)

Explanation

When multiplying complex numbers in polar form, we first multiply the moduli and then add the arguments. 

Here, r1 = √5, r2 = √5

Θ1 = 15°, Θ2 = 30°

r1r2 = √5 × √5 = 5

Θ1 + Θ2 = 15° + 30° = 45°

Therefore, √5 (cos15° + i sin15°) and √5 (cos 30° + i sin30°) = 5(cos 45° + i sin45°)

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Problem 4

Find the product of (3 -4i) and (1 +2i)

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The product of (3 -4i) and (1 +2i) is 11 + 2i

Explanation

To multiply the complex number, we use the formula;

(a + ib) (c + id) = (ac - bd) +  i(ad + bc). 

Here, a = 3, b = -4, c =1, d = 2

(ac - bd) = ((3 × 1) - (-4 × 2)) = 3 + 8 = 11

(ad + bc) = ((3 × 2) + (-4 × 1)) = 6 - 4 = 2

Therefore, the product of (3 -4i) and (1 +2i) is 11 + 2i

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Problem 5

Find the square of the complex number z = 3 + 4i

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(3 + 4i)² = -7 +24i

Explanation

(a + ib)² =  (a2 - b2) + i (2ab)

= (3² - 4i²) + i (2 × 3 × 4)

= (9 - 16) + i (24)

= -7 + 24i

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FAQs on Multiplying Complex Numbers

1.What is a complex number?

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2.What is the multiplication of complex numbers formula?

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3.What is the formula to multiply complex numbers in polar form?

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4.What is an argument in polar form?

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5.What is the value of i²?

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6.How can children in United Arab Emirates use numbers in everyday life to understand Multiplying Complex Numbers?

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7.What are some fun ways kids in United Arab Emirates can practice Multiplying Complex Numbers with numbers?

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8.What role do numbers and Multiplying Complex Numbers play in helping children in United Arab Emirates develop problem-solving skills?

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9.How can families in United Arab Emirates create number-rich environments to improve Multiplying Complex Numbers skills?

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Hiralee Lalitkumar Makwana

About the Author

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.

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Fun Fact

: She loves to read number jokes and games.

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