Last updated on July 24th, 2025
A complex number is written in the form z = a + ib, where i is the imaginary unit (i2 = -1) and a and b are real numbers. It involves applying the distributive property to compute the product of two complex numbers. In this article, let’s learn about the multiplication of complex numbers.
The multiplication of complex numbers involves finding the product of two or more complex numbers using the distributive property.
That is, for two complex numbers: z1 = a + ib and z2 = c + id, the product of z1 and z2 is z1z2 = (a + ib) (c + id).
The multiplication of complex numbers follows similar properties to the real numbers. The properties are
Commutative property: It can be stated as the order of multiplication does not affect the result. For example, z1 × z2 = z2 × z1.
Associative property: The associative property of complex numbers states that the order of grouping the complex numbers doesn't change the result. That is, z1 × (z2 × z3) = (z1 × z2) × z3.
Distributive property: The distributive property states that z1 (z2 + z3) = z1z2 + z1z3
Now, let’s learn how to multiply complex numbers in Cartesian form. In this form, we multiply the complex number term by term.
That is, if z1 = a + ib and z2 = c + id.
Then z1 × z2 = (a + ib) (c + id)
= ac + a(id) + ib(c) + i2bd
= (ac - bd) + i(ad + bc)
So, (a + ib) (c + id) = (ac - bd) + i(ad + bc)
For example, find the product of Z1 = 3 + 2i and z2 = 1 + 4i
Z1z2 = (3 + 2i) (1 + 4i)
Using the formula for multiplying complex numbers, (a + ib) (c + id) = (ac - bd) + i(ad + bc)
(3 + 2i) (1 + 4i) = ((3 × 1) - (2 × 4)) + i((3 × 4) + (2 × 1))
= (3 - 8) + i (12 + 2)
= -5 + 14i
When multiplying complex numbers in polar form, we first multiply the moduli and then add the arguments. That is, when multiplying z1 = r1eiΘ1 and z2 = r2eiΘ2
Z1z2 = r1eiΘ1 × r2eiΘ2
= (r1 r2) eiΘ1 + iΘ2
= r1r2 ei(Θ1 + Θ2)
For example, multiplying z1 = 2eiπ/6 and z2 = 3eiπ/4
z1z2 = r1r2 ei(Θ1 + Θ2)
Here, r1 = 2
r2 = 3
Θ1 = π/6
Θ2 = π/4
Multiplying moduli (r1r2) = 2 × 3 = 6
Adding the arguments = π/6 + π/4
= 2π/12 + 3π/12
= 5π/12
So, 2eiπ/6 × 3eiπ/4 = 6ei5π/12
The multiplication formula for complex numbers is (a + ib) (c + id) = (ac - bd) + i (ad + bc). When multiplying the complex number by a real number, let's consider b as 0. That is a (c + id) = ac + iad.
For example: -5i (2 + 3i)
Using the formula, a (c + id) = ac + iad.
Here, a = -5i
c = 2
d = 3i
Substituting the value, -5i (2 + 3i) = (-5i × 2) + (-5i × 3i)
= -10i + (-15i2)
Substituting i2 = -1
= -10i + 15 = 15 - 10i.
The formula for multiplying complex numbers is (a + ib) (c + id) = (ac - bd) + i(ad + bc). When squaring a complex number, consider a = c and b = d, and then the formula becomes;
(a + ib)2 = (a×a - b × b) + i(ab + ba)
= (a2 - b2) + i (2ab)
For example, squaring 4 + 5i
(a + ib)2 = (a2 - b2) + i(2ab).
So, (4 + 5i) = (42 - (5i)2) + i(2 × 4 × 5)
= (16 - 25 × i2) + 40i
= 16 - 25 + 40i
= -9 + 40i
The multiplicative inverse of a complex number z = a + ib is another complex number z-1, that is, z × z-1 = 1. For a complex number z = a + ib, the multiple inverse z-1 = z/|z|²
Here, z = a - ib, so, |z| = √a2 + b2
The formula for the multiplicative inverse: z-1 = z/|z|²
Where, conjugate: z = a - ib, and the modulus of the complex number is |z| = √a² + b²
Complex number multiplication is used in various fields, like engineering, quantum mechanics, computer graphics, etc. In this section, we will discuss them in detail.
The students usually make mistakes when multiplying complex numbers, and mostly they repeat the same mistakes. In this section, we will discuss some common mistakes and ways to avoid them in multiplying complex numbers.
Find the product of (2 + 3i) × (4 + 5i)
The product of (2 + 3i) × (4 + 5i) is -7 + 22i
To multiply the complex number, we use the formula;
(a + ib) (c + id) = (ac - bd) + i(ad + bc).
Here, a = 2, b = 3, c = 4, and d = 5
(ac - bd) = 2 × 4 - 3 × 5 = 8 - 15 = -7
(ad + bc) = 2 × 5 + 3 × 4 = 10 + 12 = 22
So, the product is -7 + 22i
Find the product of (1 + i) and (1-i) using the polar form
The product is 2
To find the product in polar form, we first convert each complex number to polar form.
For 1 + i,
r = √a2 + b2
= √1² + 1² = √2
Θ = tan-1(b/a)
= tan-1(1/1) = 45°
Therefore, 1 + i = √2(cos45° + i sin45°)
For 1 - i,
r = √1² + (-1)²
=√2
Θ = tan-1(-1/1) = -45°
Therefore, 1 + i = √2(cos(-45°) + i sin(-45°))
Here, r1r2 = √2 × √2 = 2
Θ1 + Θ2 = 45° + (-45°) = 0°
(1 + i)(1-i) = 2(cos0° + i sin0°) = 2.
Find the product of √5 (cos15° + i sin15°) and √5 (cos 30° + i sin30°)
The product of √5 (cos15° + i sin15°) and √5 (cos 30° + i sin30°) = 5(cos 45° + i sin45°)
When multiplying complex numbers in polar form, we first multiply the moduli and then add the arguments.
Here, r1 = √5, r2 = √5
Θ1 = 15°, Θ2 = 30°
r1r2 = √5 × √5 = 5
Θ1 + Θ2 = 15° + 30° = 45°
Therefore, √5 (cos15° + i sin15°) and √5 (cos 30° + i sin30°) = 5(cos 45° + i sin45°)
Find the product of (3 -4i) and (1 +2i)
The product of (3 -4i) and (1 +2i) is 11 + 2i
To multiply the complex number, we use the formula;
(a + ib) (c + id) = (ac - bd) + i(ad + bc).
Here, a = 3, b = -4, c =1, d = 2
(ac - bd) = ((3 × 1) - (-4 × 2)) = 3 + 8 = 11
(ad + bc) = ((3 × 2) + (-4 × 1)) = 6 - 4 = 2
Therefore, the product of (3 -4i) and (1 +2i) is 11 + 2i
Find the square of the complex number z = 3 + 4i
(3 + 4i)² = -7 +24i
(a + ib)² = (a2 - b2) + i (2ab)
= (3² - 4i²) + i (2 × 3 × 4)
= (9 - 16) + i (24)
= -7 + 24i
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.