Last updated on July 25th, 2025
The properties of logarithms can be used to combine and simplify logarithmic expressions. Logarithms are called the inverse functions of exponents because they reverse the effects of exponentiation. Therefore, the properties of logarithms can be drawn from the properties of exponents. We can expand a logarithmic expression into multiple ones, or combine multiple logarithms into a single one. In this article, we will explore all the properties of logarithms in detail.
The goal of each property of logarithms is to simplify and solve logarithmic equations and expressions.
For all logarithmic properties: (m, n > 0, a > 0, a ≠ 1)
Only positive real numbers can be used to define logarithms, and their bases must be positive and not equal to 1. While more properties exist, the four basic properties are listed below:
Product property:
loga mn = loga m + loga n
Condition: (m, n > 0, a > 0, a ≠ 1)
This property states that the logarithm of a product (mn) is equal to the sum of two logarithms.
Quotient property:
loga m / n = loga m - loga n
Condition: (m, n > 0, a > 0, a ≠ 1)
The quotient property states that the logarithm of a quotient (m/n) is the same as the difference between the two logarithms.
Power property:
loga( mn) = n loga m
Condition: (m, n > 0, a > 0, a ≠ 1)
The rule shows that if we move the exponent inside a logarithm to the front of a log, then the exponent will be the multiplier.
Change of base property:
logb a = logc a / logc b
Condition: (m, n > 0, a > 0, a ≠ 1)
This property states that we can convert the base of a logarithm to another base.
Other properties are also directly derived from exponent rules. The definition of logarithm is:
ax = m loga m = x
a0 = 1 loga 1 = 0
a1 = a loga a = 1
aloga x = x
logbn (am) = m ⋅ logb (a)
(Results from changing the power property and base rule).
The following table lists the properties of logarithms.
The base of the natural log is “e,” and it is expressed as loge = ln. Here, all the above properties are in the “log” form, so those are also applicable to the natural log. The natural logarithmic properties are as follows:
ln (1) = 0
Any number raised to the power of 0 is equal to 1.
ln (e) = 1
The natural log of e is always 1 because e raised to the power of 1 is equal to e itself.
ln (mn) = ln m + ln n
The natural logarithm of the product (mn) is equal to the sum of the natural logarithms of m and n.
ln (m / n) = ln m - ln n
The difference between the natural logs of m and n is equal to the division of m and n.
ln (mn) = n × ln (m)
When a number m is raised to a power n, the exponent n can be moved in front of the logarithm as a multiplier.
e(ln (x)) = x
When e is raised to the power of ln (x), the result will be x itself. Both ln and e cancel out, and we get back the number x.
The product property of log explains that the logarithm of a product is equal to the sum of the two individual logs. The property is:
loga mn = loga m + loga n
As we know, logarithmic forms are the inverse of the exponential forms.
For example, loga m = x is the inverse of ax = m.
Here, loga m = x, so ax = m
loga n = y, so ay = n
Now, we can multiply mn as:
mn = ax × ay
By using the multiplying exponents,
mn = ax + y
Now, let us convert it to logarithmic form:
loga mn = x + y
Hence, x = loga m
y = loga n
Therefore, loga mn = loga m + loga n
For instance, log(2 × 3) = log 2 + log 3 = log 6
log(2 × 3) = log 6
By applying the product property:
loga mn = loga m + loga n
log (2 × 3) = log (2) + log (3)
Now, we can use a calculator to find the values.
log(2) 0.3010
log(3) 0.4771
Next, add 0.3010 and 0.4771.
0.3010 + 0.4771 = 0.7781
log(6) 0.7781
Therefore, log (2 × 3) = log 2 + log 3 = log 6
The logarithm of a quotient results in the difference between the logarithm of the numerator and denominator. The quotient property of log is:
loga m / n = loga m - loga n
The derivation of the property is as follows:
Let loga m = x and loga n = y
The exponential forms are:
m = ax
n = ay
Now, m / n = ax / ay
By using the rule of dividing exponents,
m /n = ax - y
Next, convert it to logarithmic form:
loga m / n = loga m - loga n
For example, log (20 / 2) = log 20 - log 2
log (20 / 2) = log 10
By applying the quotient property:
loga m / n = loga m - loga n
We can use a calculator to find the value of log (20) and log (2).
log (20) 1.3010
log (2) 0.3010
Now, we can subtract:
log (20) - log (2) = 1.3010 - 0.3010 = 1.0000
Log (10) = 1
Hence, log (20 / 2) = log (20) - log (2)
According to the power property, the exponent of the argument inside the logarithm can be brought to the front of another log.
loga( mn) = n loga m
Here, the exponent n changed to the multiplier n. Let us understand the derivation of the power property.
Let loga m = x
That is, ax = m
Now we can raise both sides to the power of n:
(ax)n = mn
Now take the logarithm base a of both sides:
loga (mn) = loga (anx)
We assumed loga (m) = x, so:
loga (mn) = n loga (m)
For instance, log x3 = 3 log x
The power property is:
loga (mn) = n loga (m)
Here, base a is not given, hence it is 10 (it is a common log).
m = x
n = 3
Now, we can apply the property:
log (x3) = 3 log (x)
The change of base property helps us to change the base of a logarithm into another, which makes the calculations easier. The property is:
logb a = logc a / logc b
According to this property, the logarithm with base b can change into any base c. It states that both logs use the same new base.
The derivation of the change of base property is:
Let logb a = x, so a = bx… (1)
Let logc a = y, so a = cy … (2)
Let logc b = z, so b = cz … (3)
Now, we can replace b in the first equation with cz.
Then, a = (cz)x = czx
However, from previously, a = cy
Hence, czx = cy
Now that the bases are the same, we can equate the exponents:
zx = y x = y / z
Finally, substituting back:
logb a = logc a / logc b
For example, log4 3 = (log 3) / (log 4)
We can apply the property:
logb a = logc a / logc b
Next, substitute the values:
log4 3 = (log 3) / (log 4)
Now, we can use a calculator to find the values.
log (3) 0.4771
log (4) 0.6020
Here, we divide the two values:
log4 3 = 0.4771 / 0.6020 0.7925
If we raise 4 to the power of 0.7925:
40.7925 3
The properties of logarithms play an important role in various situations, from music to science and mathematics. Here are some real-world applications of the properties:
Understanding the key properties of logarithms helps students apply them when solving various mathematical problems. However, they often make some mistakes that lead to incorrect conclusions. Here are some common mistakes and their solutions to prevent them.
If logb 3 = a, then what is the value of log (1 / 27) in terms of a?
-3a
We are given logb 3 = a
Here, we want to find:
logb (1 / 27)
Using the quotient property of logarithms:
logb (1 / 27) = logb 1 - logb 27
Since logb 1 = 0,
logb (1 / 27) = 0 - logb 27 = - logb 27
Now, we can express 27 as a power of 3:
27 = 33
logb 27 = logb (33)
Next, apply the power property:
log (33) = 3 ⋅ logb 3 = 3a
So:
logb (1 / 27) = -3a
Hence, the answer is log (1 / 27) = -3a
Simplify log (12) = log x + log 6. Find the value of x.
x = 2
We can use the product property to find the value of x.
We can combine the two logs on the right side:
log x + log 6 = log (x 6)
Hence, the equation is:
Log 12 = log (6x)
As we know, the logarithms are equal, so their arguments must also be equal.
12 = 6x
Now, we can solve for x:
x = 12 / 6
x = 2
Therefore, the value of x is 2.
Expand log (10/2)
1 - log 2
Here, we need to expand log (10 / 2).
We can use the quotient property, which states that:
log (a / b) = log a - log b
So, the expression becomes:
log (10 / 2) = log 10 - log 2
As we know, log 10 = 1, because the base of the common logarithm is 10.
Hence, log 10 - log 2 = 1 - log 2
Therefore, the expanded expression is 1 - log 2.
Evaluate log (34).
log (34) = 4 log 3
We can use the power property to evaluate log (34).
It states that, loga( mn) = n loga m
Here, m = 3
n = 4
So, we can simplify the expressions as:
log (34) = 4 log 3
The simplified expression is 4 log 3.
If we want to find the approximate value of log 3, we can use a calculator.
log (3) 0.4771
Thus, 4 log 3 4 × 0.4771 = 1.9084
Hence, log (34) 1.9084
Evaluate using base 10: log3 9
2
The change of base property:
log3 (9) = log (9) / log (3)
Now, we can use a calculator to know the values:
log (9) 0.9542
log (3) 0.4771
log3 (9) = 0.9542 / 0.4771 2
Therefore, log3 (9) = 2
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.