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Last updated on July 25th, 2025

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Properties of Logarithms

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The properties of logarithms can be used to combine and simplify logarithmic expressions. Logarithms are called the inverse functions of exponents because they reverse the effects of exponentiation. Therefore, the properties of logarithms can be drawn from the properties of exponents. We can expand a logarithmic expression into multiple ones, or combine multiple logarithms into a single one. In this article, we will explore all the properties of logarithms in detail.

Properties of Logarithms for UAE Students
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What are the properties of Log?

The goal of each property of logarithms is to simplify and solve logarithmic equations and expressions.
 For all logarithmic properties: (m, n > 0, a > 0, a ≠ 1)
Only positive real numbers can be used to define logarithms, and their bases must be positive and not equal to 1. While more properties exist, the four basic properties are listed below: 

 

 

Product property: 


    loga mn = loga m + loga n 

Condition: (m, n > 0, a > 0, a ≠ 1)

This property states that the logarithm of a product (mn) is equal to the sum of two logarithms. 

 

 

Quotient property:


     loga m / n = loga m - loga n 

Condition: (m, n > 0, a > 0, a ≠ 1)

The quotient property states that the logarithm of a quotient (m/n) is the same as the difference between the two logarithms. 

 

 

Power property:


   loga( mn) = n loga m 

Condition: (m, n > 0, a > 0, a ≠ 1)

The rule shows that if we move the exponent inside a logarithm to the front of a log, then the exponent will be the multiplier. 

 

 

Change of base property:


   logb a = logc a / logc b 

Condition: (m, n > 0, a > 0, a ≠ 1)

This property states that we can convert the base of a logarithm to another base.  

Other properties are also directly derived from exponent rules. The definition of logarithm is: 
       ax = m  loga m = x

a0 = 1  loga 1 = 0 


a1 = a  loga a = 1


aloga x = x 


logbn  (am) = m ⋅ logb (a) 
(Results from changing the power property and base rule). 

The following table lists the properties of logarithms.  

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What are the Properties of Natural Log?

The base of the natural log is “e,” and it is expressed as loge = ln. Here, all the above properties are in the “log” form, so those are also applicable to the natural log. The natural logarithmic properties are as follows:

ln (1) = 0 

Any number raised to the power of 0 is equal to 1. 

ln (e) = 1

The natural log of e is always 1 because e raised to the power of 1 is equal to e itself. 

ln (mn) = ln m + ln n 

The natural logarithm of the product (mn) is equal to the sum of the natural logarithms of m and n. 

ln (m / n) = ln m - ln n 
The difference between the natural logs of m and n is equal to the division of m and n. 

ln (mn) = n × ln (m) 

When a number m is raised to a power n, the exponent n can be moved in front of the logarithm as a multiplier. 

e(ln (x)) = x 

When e is raised to the power of ln (x), the result will be x itself. Both ln and e cancel out, and we get back the number x. 
 

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What is the Product Property of Log?

The product property of log explains that the logarithm of a product is equal to the sum of the two individual logs. The property is:
     loga mn = loga m + loga n 

As we know, logarithmic forms are the inverse of the exponential forms. 
For example, loga m = x is the inverse of ax = m.

Here, loga m = x, so ax = m 
loga n = y, so ay = n 

Now, we can multiply mn as:  
   mn = ax × ay

By using the multiplying exponents, 
    mn = ax + y

Now, let us convert it to logarithmic form:
    loga mn = x + y 

Hence, x = loga m 
y = loga n 

Therefore, loga mn = loga m + loga n 

For instance, log(2 × 3) = log 2 + log 3  = log 6
  log(2 × 3) = log 6 

By applying the product property: 
     loga mn = loga m + loga n 

log (2 × 3) = log (2) + log (3) 

Now, we can use a calculator to find the values.
   log(2)  0.3010
   log(3)  0.4771

Next, add 0.3010 and 0.4771.
    0.3010 + 0.4771 = 0.7781

log(6)  0.7781

Therefore, log (2 × 3) = log 2 + log 3  = log 6
 

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What is the Quotient Property of Log?

The logarithm of a quotient results in the difference between the logarithm of the numerator and denominator. The quotient property of log is:
        loga m / n = loga m - loga n 

The derivation of the property is as follows:
 
Let loga m = x and loga n = y
 The exponential forms are: 
   m = ax
    n = ay 

Now, m / n = ax / ay

By using the rule of dividing exponents, 
    m /n = ax - y 

Next, convert it to logarithmic form:
     loga m / n = loga m - loga n 

For example, log (20 / 2) = log 20 - log 2  
    log (20 / 2) = log 10 

By applying the quotient property: 
    loga m / n = loga m - loga n 

We can use a calculator to find the value of log (20) and log (2). 
   log (20)  1.3010
   log (2)  0.3010 

Now, we can subtract:
    log (20) - log (2) = 1.3010 - 0.3010 = 1.0000
 
    Log (10) = 1 

Hence, log (20 / 2) = log (20) - log (2)  

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What is the Power Property of Logarithms?

According to the power property, the exponent of the argument inside the logarithm can be brought to the front of another log. 
  
     loga( mn) = n loga m 
 
Here, the exponent n changed to the multiplier n. Let us understand the derivation of the power property. 

Let loga m = x
That is, ax = m 

Now we can raise both sides to the power of n:
   (ax)n = mn

Now take the logarithm base a of both sides:
    loga (mn) = loga (anx)

We assumed loga (m) = x, so: 
 
    loga (mn) = n loga (m)

For instance, log x3 = 3 log x 
The power property is:
     loga (mn) = n loga (m)
Here, base a is not given, hence it is 10 (it is a common log). 
m = x
n = 3 

Now, we can apply the property: 
   log (x3) = 3 log (x)
 

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How to Change the Base Property of Log?

The change of base property helps us to change the base of a logarithm into another, which makes the calculations easier. The property is:
    
    logb a = logc a / logc b 

According to this property, the logarithm with base b can change into any base c. It states that both logs use the same new base.  

The derivation of the change of base property is:

Let logb a = x, so a = bx… (1)
Let logc a = y, so a = cy … (2) 
Let logc b = z, so b = cz … (3)
    
Now, we can replace b in the first equation with cz.
Then, a = (cz)x = czx
However, from previously, a = cy

Hence, czx = cy
Now that the bases are the same, we can equate the exponents:
 zx = y   x = y / z

Finally, substituting back: 
          logb a = logc a / logc b  

For example, log4 3 = (log 3) / (log 4) 
We can apply the property:
       logb a = logc a / logc b 
Next, substitute the values:
      log4 3 = (log 3) / (log 4)

Now, we can use a calculator to find the values. 
log (3)  0.4771 
log (4)  0.6020 

Here, we divide the two values:
   log4 3 = 0.4771 / 0.6020  0.7925 
If we raise 4 to the power of 0.7925:
 40.7925  3  
 

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Real-Life Applications of Properties of Logarithms

The properties of logarithms play an important role in various situations, from music to science and mathematics. Here are some real-world applications of the properties:
 

  • Seismologists can use the properties of logarithms to measure the magnitude of earthquakes. For example, to compare the magnitudes, they can use the power and properties of logs, which are measured on a logarithmic scale. 

     
  • Scientists can use the properties of logarithms to measure the alkalinity or acidity of various solutions in their laboratories. For instance, the acidity of a lemon solution is measured using the pH scale, then, 
     pH = -log10[H+] 
    pH = - log (0.001) = -(-3) = 3
    This means that the pH of lemon juice is 3, which makes it acidic. 

     
  • To make long-term predictions and plans related to population, officials can use the properties of logarithms. This is because the properties help them to simplify complex population models. 
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Common Mistakes and How to Avoid Them on Properties of Logarithms

Understanding the key properties of logarithms helps students apply them when solving various mathematical problems. However, they often make some mistakes that lead to incorrect conclusions. Here are some common mistakes and their solutions to prevent them.
 

Mistake 1

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 Incorrectly Applying Product Property 
 

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 Students should properly learn the product properties and their usage. If they misinterpret the property, the answer will be wrong. 
For example, log (10) = log (5) + log (2) 
This is the correct answer. However, if they mistakenly write it as:
log (10) = log (5) + log (5) 
This is the wrong answer. 
 

Mistake 2

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Forgetting the Quotient Property  
 

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Always remember the quotient property, which states that the logarithm of a quotient (m/n) is the same as the difference between the two logarithms. If students fail to remember the rule, they derive incorrect results. 
For instance, log (10 / 2) = log 10 - log 2 
This is correct. 
Also, remember to subtract in the correct order as in the equation.  
 

Mistake 3

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Neglecting the Exponent in the Power Property 
 

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Students should pull out the exponent inside the logarithm and place it in front of the log. Forgetting to bring it out will lead to wrong answers. Moreover, the pulled-out exponent becomes the multiplier in front of the log. 
For example, log (x4) can be written as:
log (x4) = 4 log x
 

Mistake 4

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 Trying to Use Different Bases 
 

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 Keep in mind that, according to the change of base property, the bases of both logs must be the same. Sometimes, students use different bases, which do not apply to the rule. 
For example, log6 2 = log(2) / log(6)
This is incorrect because the bases are different. 
The correct answer is:
    log6 2 = log 2 /log 6 
 

Mistake 5

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 Forgetting the Exponential Form 
 

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Remember that logarithms are the inverse of the exponentials. Hence, students should not forget the exponential form. 
For instance, the exponential form of loga m = x: 
     ax = m  
 

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Solved Examples of Properties of Logarithms

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Problem 1

If logb 3 = a, then what is the value of log (1 / 27) in terms of a?

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-3a 
 

Explanation

We are given logb 3 = a
Here, we want to find:
    logb (1 / 27) 
Using the quotient property of logarithms: 

   logb (1 / 27) = logb 1 - logb 27 
 
Since logb 1 = 0, 
    logb (1 / 27) = 0 - logb 27 = - logb 27

Now, we can express 27 as a power of 3:   
    27 = 33
    logb 27 = logb (33) 

Next, apply the power property:  
    log (33) = 3 ⋅ logb 3 = 3a 

So:
   logb (1 / 27) = -3a

Hence, the answer is log (1 / 27) = -3a  
 

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Problem 2

Simplify log (12) = log x + log 6. Find the value of x.

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 x = 2
 

Explanation

 We can use the product property to find the value of x. 
We can combine the two logs on the right side:
     log x + log 6 = log (x 6)

Hence, the equation is:
    Log 12 = log (6x) 

As we know, the logarithms are equal, so their arguments must also be equal. 
       12 = 6x 
 
Now, we can solve for x:
      x = 12 / 6 
       x = 2 

Therefore, the value of x is 2. 
 

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Problem 3

Expand log (10/2)

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1 - log 2
 

Explanation

Here, we need to expand log (10 / 2).
We can use the quotient property, which states that:
     log (a / b) = log a - log b

So, the expression becomes:
      log (10 / 2) = log 10 - log 2

As we know, log 10 = 1, because the base of the common logarithm is 10. 

Hence, log 10 - log 2 = 1 - log 2

Therefore, the expanded expression is 1 - log 2. 
 

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Problem 4

Evaluate log (34).

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 log (34) = 4 log 3 
 

Explanation

We can use the power property to evaluate log (34). 
     It states that, loga( mn) = n loga m 

Here, m = 3 
n = 4 
So, we can simplify the expressions as:
    log (34) = 4 log 3 

The simplified expression is 4 log 3. 
If we want to find the approximate value of log 3, we can use a calculator. 
   log (3)  0.4771

Thus, 4 log 3  4 × 0.4771 = 1.9084 

Hence, log (34)  1.9084  
 

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Problem 5

Evaluate using base 10: log3 9

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2
 

Explanation

The change of base property:   
    log3 (9) = log (9) / log (3) 

Now, we can use a calculator to know the values:
   log (9)  0.9542 
   log (3)  0.4771

   log3 (9) = 0.9542 / 0.4771  2
Therefore, log3 (9) = 2
 

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FAQs on Properties of Logarithms

1.List the four main properties of logarithms.

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2.Can the quotient property be used with addition?

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3.Explain the power property of logarithms.

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4.Which property is used to change the base?

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5.List the natural logarithmic properties.

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6.How does learning Algebra help students in United Arab Emirates make better decisions in daily life?

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7.How can cultural or local activities in United Arab Emirates support learning Algebra topics such as Properties of Logarithms?

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8.How do technology and digital tools in United Arab Emirates support learning Algebra and Properties of Logarithms?

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9.Does learning Algebra support future career opportunities for students in United Arab Emirates?

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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: He loves to play the quiz with kids through algebra to make kids love it.

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